
配置RIPv1协议,宣告主类网络号下:
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R2#sh ip route1 ~4 n7 @1 L; r5 a7 N- M
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192.168.10.0/30 is subnetted, 2 subnets
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192.168.10.4 is directly connected, Serial0/01 E: W8 b% o$ x" r5 [+ H
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192.168.10.8 is directly connected, Serial0/10 z% W2 R; ]" o" `
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R3#sh ip route
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192.168.10.0/24 is variably subnetted, 3 subnets, 2 masks2 v7 X' h1 F/ F4 K: Q7 S
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/ l6 G7 ~/ c$ w192.168.10.32/27 is directly connected, Loopback0
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% [% x: s7 @' E6 M4 M192.168.10.4/30 [120/1] via 192.168.10.9, 00:00:14, Serial0/0
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192.168.10.8/30 is directly connected, Serial0/0 Q: x5 Y, U# W! J1 y( g
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环境二:4 X1 P& j' E D4 o9 F
R1#sh ip route
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4 _+ B2 ]' [4 V0 R" ]- V192.168.10.0/24 [120/1] via 10.1.1.2, 00:00:19, Serial0/0
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# J- E5 d' O w9 `& y( `* j) u: c172.16.0.0/24 is subnetted, 1 subnets. {* ]9 h: g. S+ Y
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1 ]- ]6 D/ m- ]. r; r172.16.10.0 is directly connected, Loopback0# C8 _1 q; Y0 H% G& Z
' |8 q& S0 j4 u6 A5 F8 B' w10.0.0.0/24 is subnetted, 1 subnets, G! c. s, g ?
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10.1.1.0 is directly connected, Serial0/0
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R2#sh ip route }/ q0 k5 F# y: @- ?) _9 N4 D2 j* {
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192.168.10.0/26 is subnetted, 1 subnets
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+ ~/ d$ S% ]; T$ ?192.168.10.64 is directly connected, Loopback09 M! q: [8 Q* r$ }2 C3 ~ S9 i
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172.16.0.0/16 [120/1] via 10.1.1.1, 00:00:00, Serial0/0, `4 t& v( A4 F
v& {& ?5 b1 }, m* s10.0.0.0/24 is subnetted, 1 subnets
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# G4 o' c4 T1 c# C4 \3 y' |10.1.1.0 is directly connected, Serial0/0
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2 [4 z2 W7 O; I环境一中,R2直连30位掩码,配置RIPv1无法学到R3上192.168.10.33/27位掩码的网络信息。* ^3 |( Z) @% F# F# z& M8 O) G! k
环境二中,R1直连24为掩码,同样在RIPv1下能够学到R2上192.168.10.0/24这个主类网络信息。
) i2 ]. j5 Z+ q& Y猜测:在RIPv1中,能学到远端掩码大于直连掩码的网络信息,并且学到的掩码大小不超过直连网络掩码位数。
' l6 f4 I6 c0 m) j9 P4 K1. 求证这个结论是否正确?
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8 {4 e/ O% y* Q2. 对于RIP协议与能学到的子网信息的关系,欢迎网友总结与补充。 |
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