
公司部署了赛门铁克网络准入,接入层交换机内存使用率会每天增高.经查看是主要是随着运行时间增长,EAP进程的内存占用率会越来越高,,最终到达90%多.以下是间隔几分钟的命令输出,可以看到EAP占用的内存随着count=1666到1676,holding内存也不断增大.现在我只知道是因为准入导致内存率高,但不懂为什么会这样?有没有人遇到相似情况.另外show processes memory 这个命令的输出怎么解读?pc=0x是指什么?count是指什么计数?谢谢.
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show processes memory 105
! x" d3 @$ \& i0 ~7 k0 @7 ]5 uProcess ID: 105
0 g" v# q3 E2 u; NProcess Name: EAP Framework
+ b* d4 i0 p& ?1 STotal Memory Held: 776524 bytes
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Processor memory Holding = 776524 bytes! A' \6 l+ O) Y. A
pc = 0x0032A6E0, size = 459088, count = 1666
5 b' `/ w- K5 Q: Y& Qpc = 0x00847DE0, size = 65580, count = 1
8 d' K& s( R4 ~8 a) N+ X% z6 ppc = 0x0084C344, size = 40088, count = 2
2 W0 @3 V* D2 N, ?6 G% wpc = 0x0083933C, size = 32812, count = 17 y; d2 B+ ^1 C: F3 V$ l4 Z$ r( Y
pc = 0x0032AE0C, size = 30576, count = 333
5 m9 L- u1 q3 r5 vpc = 0x0032AE80, size = 30128, count = 333
% z( ^, |2 ~( l4 [: bpc = 0x0032AEF0, size = 29860, count = 333
G6 Q) R$ U) U' M l+ ]' d8 s2 Z' apc = 0x0032AF3C, size = 29456, count = 3334 i* c8 Y6 O5 p' X4 e* i3 t
pc = 0x0084C314, size = 20044, count = 1. I! Y1 [; q& }) j& E5 Q
pc = 0x0084DDF8, size = 10044, count = 1
& T4 p$ q, ^( g' e9 d! m. ~$ Cpc = 0x0084DE2C, size = 10044, count = 1$ U/ v% h+ i( Q0 s7 u& ~
pc = 0x007AB274, size = 6088, count = 2
- A0 I# d, @- |7 a5 J, Gpc = 0x00BD308C, size = 6044, count = 1
: b0 D; z2 p$ Zpc = 0x007AB240, size = 4604, count = 1; T m, L, Y6 f9 }$ Q9 Q0 D
pc = 0x00839D0C, size = 1068, count = 1
" r& ~7 S9 X g. V* D+ Kpc = 0x00B9CA00, size = 684, count = 1
- G" O6 R* P4 i( Ppc = 0x00B9EF94, size = 180, count = 1
! i* d: J0 y, Z o hpc = 0x00BF0EE4, size = 136, count = 1
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I/O memory Holding = 0 bytes
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" V9 x1 T: L, k: V A3 rDriver text memory Holding = 0 bytes
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5 K" d) a6 y1 s4 h' _' f) |- Bshow processes memory 105 + E# v f" ?. U( |8 n
Process ID: 1057 {7 L4 @+ g' ?. f1 Y1 z
Process Name: EAP Framework% i" d8 l7 [8 ^0 o; M
Total Memory Held: 780080 bytes) v) e$ U* N [
# [6 d# \7 M4 C$ t) R4 EProcessor memory Holding = 780080 bytes
6 G j( U! o+ B* d x9 Z" v8 Jpc = 0x0032A6E0, size = 461820, count = 1676 Y- F" e& q% A( e1 Y% f" l
pc = 0x00847DE0, size = 65580, count = 11 Z% f" `4 {: f
pc = 0x0084C344, size = 40088, count = 2( Y! _6 `3 m& c; }" ~* `1 R6 G
pc = 0x0083933C, size = 32812, count = 1) ]6 M( Y& \5 y6 b
pc = 0x0032AE0C, size = 30816, count = 335
3 v+ h4 l7 l1 U. d( Ypc = 0x0032AE80, size = 30332, count = 335
- T. A8 H* N' ~% W* I3 kpc = 0x0032AEF0, size = 30064, count = 335& N z! x5 |- |/ c+ H1 d5 n& Y5 S/ n
pc = 0x0032AF3C, size = 29632, count = 335
0 B3 A& x8 l2 b& X* L& npc = 0x0084C314, size = 20044, count = 1: h7 n- W6 X! H9 C
pc = 0x0084DDF8, size = 10044, count = 1
3 ?% ~3 g; u/ X+ [! t, d1 D2 T/ y4 d" kpc = 0x0084DE2C, size = 10044, count = 1
7 ~+ R/ ^; O O' d% Epc = 0x007AB274, size = 6088, count = 2
# t) A+ |( k4 y9 e/ I& Gpc = 0x00BD308C, size = 6044, count = 1: C$ {/ C! o3 a* F* V8 w# u7 ^9 A
pc = 0x007AB240, size = 4604, count = 1* l0 C; [* e( P* b" q
pc = 0x00839D0C, size = 1068, count = 13 g! A$ C& J, {5 ?0 R( e
pc = 0x00B9CA00, size = 684, count = 1, |% n8 @4 ^5 p/ w: `3 _
pc = 0x00B9EF94, size = 180, count = 1+ I& {. c! p8 y$ B
pc = 0x00BF0EE4, size = 136, count = 1, _+ n( L3 T, k& }- D; n
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I/O memory Holding = 0 bytes8 [ g9 j" G; m6 t* f
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Driver text memory Holding = 0 bytes |
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